open import 1Lab.Path
open import 1Lab.Type

module 1Lab.HLevel where

h-Levels🔗

The “homotopy level” (h-level for short) of a type is a measure of how truncated it is, where the numbering is offset by 2. Specifically, a (-2)-truncated type is a type of h-level 0. In another sense, h-level measures how “homotopically interesting” a given type is:

  • The contractible types are maximally uninteresting because there is only one.

  • The only interesting information about a proposition is whether it is inhabited.

  • The interesting information about a set is the collection of its inhabitants.

  • The interesting information about a groupoid includes, in addition to its inhabitants, the way those are related by paths. As an extreme example, the delooping groupoid of a group – for instance, the circle – has uninteresting points (there’s only one), but interesting loops.

For convenience, we refer to the collection of types of h-level nn as homotopy (n2)(n-2)-types. For instance: “The sets are the homotopy 0-types”. The use of the 2-2 offset is so the naming here matches that of the HoTT book.

The h-levels are defined by induction, where the base case are the contractible types.

record is-contr {} (A : Type ) : Type  where
  constructor contr
  field
    centre : A
    paths : (x : A)  centre  x

open is-contr public

A contractible type is one for which the unique map X → ⊤ is an equivalence. Thus, it has “one element”. This doesn’t mean that we can’t have “multiple”, distinctly named, inhabitants of the type; It means any inhabitants of the type must be connected by a path, and this path must be picked uniformly.

module _ where
  data [0,1] : Type where
    ii0 : [0,1]
    ii1 : [0,1]
    seg : ii0  ii1

An example of a contractible type that is not directly defined as another name for is the unit interval, defined as a higher inductive type.

  interval-contractible : is-contr [0,1]
  interval-contractible .centre = ii0
  interval-contractible .paths ii0 i = ii0
  interval-contractible .paths ii1 i = seg i
  interval-contractible .paths (seg i) j = seg (i  j)

A type is (n+1)-truncated if its path types are all n-truncated. However, if we directly take this as the definition, the types we end up with are very inconvenient! That’s why we introduce this immediate step: An h-proposition, or proposition for short, is a type where any two elements are connected by a path.

is-prop :  {}  Type   Type _
is-prop A = (x y : A)  x  y

With this, we can define the is-hlevel predicate. For h-levels greater than zero, this definition results in much simpler types!

is-hlevel :  {}  Type   Nat  Type _
is-hlevel A 0 = is-contr A
is-hlevel A 1 = is-prop A
is-hlevel A (suc n) = (x y : A)  is-hlevel (Path A x y) n

Since types of h-level 2 are very common, they get a special name: h-sets, or just sets for short. This is justified because we can think of classical sets as being equipped with an equality proposition x=yx = y - having propositional paths is exactly the definition of is-set. The universe of all types that are sets, is, correspondingly, called Set.

is-set :  {}  Type   Type 
is-set A = is-hlevel A 2

Similarly, the types of h-level 3 are called groupoids.

is-groupoid :  {}  Type   Type 
is-groupoid A = is-hlevel A 3

private
  variable
     : Level
    A : Type 

Preservation of h-levels🔗

If a type is of h-level nn, then it’s automatically of h-level k+nk+n, for any kk. We first prove a couple of common cases that deserve their own names:

is-contr→is-prop : is-contr A  is-prop A
is-contr→is-prop C x y i =
  hcomp  j  λ { (i = i0)  C .paths x j
                 ; (i = i1)  C .paths y j
                 } )
        (C .centre)

This enables another useful characterisation of being a proposition, which is that the propositions are precisely the types which are contractible when they are inhabited:

contractible-if-inhabited :  {} {A : Type }  (A  is-contr A)  is-prop A
contractible-if-inhabited cont x y = is-contr→is-prop (cont x) x y

The proof that any contractible type is a proposition is not too complicated. We can get a line connecting any two elements as the lid of the square below:

This is equivalently the composition of sym (C .paths x) ∙ C.paths y - a path xyx \to y which factors through the centre. The direct cubical description is, however, slightly more efficient.

is-prop→is-set : is-prop A  is-set A
is-prop→is-set h x y p q i j =
  hcomp  k  λ { (i = i0)  h x (p j) k
                 ; (i = i1)  h x (q j) k
                 ; (j = i0)  h x x k
                 ; (j = i1)  h x y k
                 })
        x

The proof that any proposition is a set is slightly more complicated. Since the desired homotopy p ≡ q is a square, we need to describe a cube where the missing face is the square we need. I have painstakingly illustrated it here:

To set your perspective: You are looking at a cube that has a transparent front face. The front face has four x corners, and four λ i → x edges. Each double arrow pointing from the front face to the back face is one of the sides of the composition. They’re labelled with the terms in the hcomp for is-prop→is-set: For example, the square you get when fixing i = i0 is on top of the diagram. Since we have an open box, it has a lid — which, in this case, is the back face — which expresses the identification we wanted: p ≡ q.

With these two base cases, we can prove the general case by recursion:

is-hlevel-suc :  {} {A : Type } (n : Nat)  is-hlevel A n  is-hlevel A (suc n)
is-hlevel-suc 0 x = is-contr→is-prop x
is-hlevel-suc 1 x = is-prop→is-set x
is-hlevel-suc (suc (suc n)) h x y = is-hlevel-suc (suc n) (h x y)

By another inductive argument, we can prove that any offset works:

is-hlevel-+ :  {} {A : Type } (n k : Nat)  is-hlevel A n  is-hlevel A (k + n)
is-hlevel-+ n zero x    = x
is-hlevel-+ n (suc k) x = is-hlevel-suc _ (is-hlevel-+ n k x)

A very convenient specialisation of the argument above is that if AA is a proposition, then it has any non-zero h-level:

is-prop→is-hlevel-suc
  :  {} {A : Type } {n : Nat}  is-prop A  is-hlevel A (suc n)
is-prop→is-hlevel-suc {n = zero} aprop = aprop
is-prop→is-hlevel-suc {n = suc n} aprop =
  is-hlevel-suc (suc n) (is-prop→is-hlevel-suc aprop)

Furthermore, by the upwards closure of h-levels, we have that if AA is an n-type, then paths in AA are also nn-types. This is because, by definition, the paths in a nn-type are “(n1)(n-1)-types”, which is-hlevel-suc extends into nn-types.

Path-is-hlevel :  {} {A : Type } (n : Nat)  is-hlevel A n  {x y : A}
                is-hlevel (x  y) n
Path-is-hlevel zero ahl =
  contr (is-contr→is-prop ahl _ _)
        λ x  is-prop→is-set (is-contr→is-prop ahl) _ _ _ x
Path-is-hlevel (suc n) ahl = is-hlevel-suc (suc n) ahl _ _

Path-p-is-hlevel :  {} {A : I  Type } (n : Nat)
                  is-hlevel (A i1) n
                  {x : A i0} {y : A i1}
                  is-hlevel (PathP A x y) n
Path-p-is-hlevel {A = A} n ahl {x} {y} =
  subst  e  is-hlevel e n) (sym (PathP≡Path A x y)) (Path-is-hlevel n ahl)

is-hlevel is a proposition🔗

Perhaps surprisingly, “being of h-level n” is a proposition, for any n! To get an intuitive feel for why this might be true before we go prove it, I’d like to suggest an alternative interpretation of the proposition is-hlevel A n: The type A admits unique fillers for any n-cube.

A contractible type is one that has a unique point: It has a unique filler for the 0-cube, which is a point. A proposition is a type that admits unique fillers for 1-cubes, which are lines: given any endpoint, there is a line that connects them. A set is a type that admits unique fillers for 2-cubes, or squares, and so on.

Since these fillers are unique, if a type has them, it has them in at most one way!

is-contr-is-prop : is-prop (is-contr A)
is-contr-is-prop {A = A} (contr c₁ h₁) (contr c₂ h₂) i =
  record { centre = h₁ c₂ i
         ; paths = λ x j  hcomp  k  λ { (i = i0)  h₁ (h₁ x j) k
                                          ; (i = i1)  h₁ (h₂ x j) k
                                          ; (j = i0)  h₁ (h₁ c₂ i) k
                                          ; (j = i1)  h₁ x k })
                                 c₁
         }

First, we prove that being contractible is a proposition. Next, we prove that being a proposition is a proposition. This follows from is-prop→is-set, since what we want to prove is that h₁ and h₂ always give homotopic paths.

is-prop-is-prop : is-prop (is-prop A)
is-prop-is-prop {A = A} h₁ h₂ i x y = is-prop→is-set h₁ x y (h₁ x y) (h₂ x y) i

Now we can prove the general case by the same inductive argument we used to prove h-levels can be raised:

is-hlevel-is-prop :  {} {A : Type } (n : Nat)  is-prop (is-hlevel A n)
is-hlevel-is-prop 0 = is-contr-is-prop
is-hlevel-is-prop 1 = is-prop-is-prop
is-hlevel-is-prop (suc (suc n)) x y i a b =
  is-hlevel-is-prop (suc n) (x a b) (y a b) i

Dependent h-Levels🔗

In cubical type theory, it’s natural to consider a notion of dependent h-level for a family of types, where, rather than having (e.g.) Paths for any two elements, we have PathPs. Since dependent contractibility doesn’t make a lot of sense, this definition is offset by one to start at the propositions.

is-hlevel-dep :  { ℓ'} {A : Type }  (A  Type ℓ')  Nat  Type _

is-hlevel-dep B zero =
   {x y} (α : B x) (β : B y) (p : x  y)
   PathP  i  B (p i)) α β

is-hlevel-dep B (suc n) =
   {a0 a1} (b0 : B a0) (b1 : B a1)
   is-hlevel-dep {A = a0  a1}  p  PathP  i  B (p i)) b0 b1) n

It’s sufficient for a type family to be of an h-level everywhere for the whole family to be the same h-level.

is-prop→pathp :  {B : I  Type }  ((i : I)  is-prop (B i))
               (b0 : B i0) (b1 : B i1)
               PathP  i  B i) b0 b1
is-prop→pathp {B = B} hB b0 b1 = to-pathp (hB _ _ _)

The base case is turning a proof that a type is a proposition uniformly over the interval to a filler for any PathP.

is-hlevel→is-hlevel-dep
  :  { ℓ'} {A : Type } {B : A  Type ℓ'}
   (n : Nat)  ((x : A)  is-hlevel (B x) (suc n))
   is-hlevel-dep B n
is-hlevel→is-hlevel-dep zero hl α β p = is-prop→pathp  i  hl (p i)) α β
is-hlevel→is-hlevel-dep {A = A} {B = B} (suc n) hl {a0} {a1} b0 b1 =
  is-hlevel→is-hlevel-dep n  p  helper a1 p b1)
  where
    helper : (a1 : A) (p : a0  a1) (b1 : B a1)
            is-hlevel (PathP  i  B (p i)) b0 b1) (suc n)
    helper a1 p b1 =
      J  a1 p   b1  is-hlevel (PathP  i  B (p i)) b0 b1) (suc n))
         _  hl _ _ _) p b1